What happens when you attempt to compile and run the following code?
#include <iostream>
#include <set>
#include <vector>
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<int>v(t, t+10);
multiset<int> s1(v.begin(),v.end());
s1.insert(v.begin(),v.end());
pair<multiset<int>::iterator,multiset<int>::iterator> range;
range = s1.equal_range(6);
while (range.first != range.second) {
cout<<*range.first<<" "; range.first++;
}
return 0;
}
A
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out<<val<<" ";
}
};
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() {
return start++ ; }};
int main() {
vector<int> v1(10);
generate(v1.rbegin(), v1.rend(), Sequence(1));
rotate(v1.begin(),v1.begin() + 1, v1.end() );
for_each(v1.begin(), v1.end(), Out<int>(cout) );cout<<endl;
return 0;
}
Program outputs:
C
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <fstream>
#include <string>
#include <list>
#include <algorithm>
#include <iomanip>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };
int main () {
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out", ios::trunc|ios::out);
list<B> l(t, t+10);
for_each(l.begin(), l.end(), Out<B>(f));
f.close();
f.open("test.out");
for( ; f.good() ; ) {
B i;
f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}
D
What will happen when you attempt to compile and run the code below, assuming that you enter
the following sequence: one two three<enter>?
#include <iostream>
#include <string>
using namespace std;
int main ()
{
string a;
cin>>a;
cout<<a<<endl;
return 0;
}
Program will output:
A
What will happen when you attempt to compile and run the following code?
#include <iostream>
#include <map>
#include <vector>
#include <sstream>
#include <string>
using namespace std;
int main() {
int t[] = { 3, 4, 2, 1, 0, 3, 4, 1, 2, 0 };
vector<int> v(t, t + 10);
multimap<int, string> m;
for (vector<int>::iterator i = v.begin(); i != v.end(); i++) {
stringstream s;s << *i << *i;
m.insert(pair<int, string>(*i, s.str()));
}
pair<multimap<int, string>::iterator, multimap<int, string>::iterator> range;
range = m.equal_range(2);
for (multimap<int, string>::iterator i = range.first; i != range.second; i++) {
cout << i?>first << " ";
}
return 0;
}
The output will be:
A
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val>v.val;} };
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;}
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
B t2[]={5,6,8,2,1};
vector<B> v1(10,0);
sort(t1, t1+5);
sort(t2, t2+5);
set_intersection(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
D
What happens when you attempt to compile and run the following code?
#include <list>
#include <vector>
#include <iostream>
using namespace std;
int main ()
{
int t[] = {1, 2 ,3 ,4 ,5};
vector<int>v1(t, t+5);
list<int>l1;
l1.assign(v1.end(), v1.begin());
for(int i=0; i<l1.size(); i++)
{
cout<<l1.at(i)<<" ";
}
cout<<endl;
return 0;
}
C
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;} bool operator < (const B & v) const { return val<v.val;} };
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;}
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
B t1[]={3,2,4,1,5};
B t2[]={6,10,8,7,9};
vector<B> v1(10);
sort(t1, t1+5);
sort(t2, t2+5);
merge(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<B>(cout));cout<<endl;
return 0;
}
Program outputs:
E
Which sentence is correct about the code below?
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
class A {
int a;
public:
A(int a) : a(a) {}
int getA() const { return a; }
void setA(int a) { this?>a = a; }
/* Insert Code Here */
};
struct add10 { void operator()(A & a) { a.setA(a.getA() + 10); } };
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector<A> v1(t, t + 10);
for_each(v1.begin(), v1.end(), add10());
vector<A>::iterator it = find(v1.begin(), v1.end(), A(7));
cout << it?>getA() << endl;
return 0;
}
B
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
void multiply (int a) {
a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector<int> v1(t, t+10);
for_each(v1.begin(), v1.end(), multiply);
iter_swap(v1.begin(),t+9);
for_each(v1.begin(), v1.end(), myfunction);
return 0;
}
Program outputs:
A
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={3,2,4,1,5,10,9,7,8,6};
vector<int> v1(t,t+10);
cout<<*max_element(v1.begin(), v1.end());
return 0;
}
Program outputs:
D
What happens when you attempt to compile and run the following code?
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t1[]={3,2,4,1,5};
int t2[]={5,6,8,2,1};
vector<int> v1(10);
sort(t1, t1+5);
sort(t2, t2+5);
set_intersection(t1,t1+5,t2,t2+5,v1.begin());
for_each(v1.begin(), v1.end(), Out<int>(cout));cout<<endl;
return 0;
}
Program outputs:
E
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
#include <deque>
#include <set>
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector<int> v1(t, t + 10);
deque<int> d1(t, t + 10);
set<int> s1(t, t + 10);
for_each(v1.begin(), v1.end(), myfunction); // Line I
for_each(d1.begin(), d1.end(), myfunction); // Line II
for_each(s1.begin(), s1.end(), myfunction); // Line III
return 0;
}
A
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <map>
using namespace std;
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
map<int, int> m;
for(int i=0; i < 10; i++) {
m[i]=t[i];
}
pair<const int,int> p(5,5);
map<int, int>::iterator it = find(m.begin(), m.end(), p);
if (it != m.end())
{
cout<<it?>first<<endl;
}
else
{
cout<<"Not found!\n";
}
return 0;
}
Program outputs:
B
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
#include <set>
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
set<int> s1(t, t+10);
vector<int> v1(s1.rbegin(), s1.rend());
swap_ranges(s1.begin(), s1.end(), v1.begin());
for_each(v1.begin(), v1.end(), myfunction);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:
B