What will the variable "age" be in class B?
class A {
int x;
protected:
int y;
public:
int age;
A () { age=5; };
};
class B : public A {
string name;
public:
B () { name="Bob"; };
void Print() {
cout << name << age;
}
};
A
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class complex{
double re, im;
public:
complex() : re(1),im(0.4) {}
complex operator?(complex &t);
void Print() { cout << re << " " << im; }
};
complex complex::operator? (complex &t){
complex temp;
temp.re = this?>re ? t.re;
temp.im = this?>im ? t.im;
return temp;
}
int main(){
complex c1,c2,c3;
c3 = c1 ? c2;
c3.Print();
}
C
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class complex{
double re;
double im;
public:
complex() : re(0),im(0) {}
complex(double x) { re=x,im=x;};
complex(double x,double y) { re=x,im=y;}
void print() { cout << re << " " << im;}
};
int main(){
complex c1;
c1 = 3.0;
c1.print();
return 0;
}
C
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
void fun(int);
int main()
{
int a=0;
fun(a);
return 0;
}
void fun(int n)
{
if(n < 2)
{
fun(++n);
cout << n;
}
}
A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int s(int n);
int main()
{
int a;
a = 3;
cout << s(a);
return 0;
}
int s(int n)
{
if(n == 0) return 1;
return s(n?1)*n;
}
B
What will be the output of the program?
#include <iostream>
using namespace std;
int fun(int);
int main()
{
cout << fun(5);
return 0;
}
int fun(int i)
{
return i*i;
}
A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define FUN(arg) if(arg) cout<<"Test";
int main()
{
int i=1;
FUN(i<3);
return 0;
}
D
What will the variable "y" be in class B?
class A {
int x;
protected:
int y;
public:
int age;
};
class B : private A {
string name;
public:
void Print() {
cout << name << age;
}
};
B
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
float x=3.5,y=1.6;
int i,j=2;
i = x + j + y;
cout << i;
return 0;
}
A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main(){
int i = 1;
if (i==1) {
cout << i;
} else {
cout << i-1;
}
return 0;
}
B
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class complex{
double re, im;
public:
complex() : re(1),im(0.4) {}
complex operator+(complex &t);
void Print() { cout << re << " " << im; }
};
complex complex::operator+ (complex &t){
complex temp;
temp.re = this?>re + t.re;
temp.im = this?>im + t.im;
return temp;
}
int main(){
complex c1,c2,c3;
c3 = c1 + c2;
c3.Print();
}
B
What happens when you attempt to compile and run the following code?
#include <cstdlib>
#include <iostream>
using namespace std;
float* sum(float a,float b);
float* sum(float a,float b)
{
float *f = new float;
*f = a+b;
return f;
}
int main()
{
float a,b,*f;
a = 1.5; b = 3.4;
f = sum(a,b);
cout<<*f;
return 0;
}
B
Which statement should be added in the following program to make work it correctly?
using namespace std;
int main (int argc, const char * argv[])
{
cout<<"Hello";
}
C
What is the output of the program?
#include <iostream>
using namespace std;
int main()
{
int tab[4]={10,20,30,40};
tab[1]=10;
int *p;
p=&tab[0];
cout<<*p;
return 0;
}
A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int fun(int x) {
return 2*x;
}
int main(){
int i;
i = fun(1) & fun(0);
cout << i;
return 0;
}
A